24b^2=6

Solution for 24b^2=6 equation:

24b^2=6

We move all terms to the left:

24b^2-(6)=0

a = 24; b = 0; c = -6;
Δ = b2-4ac
Δ = 02-4·24·(-6)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24}{2*24}=\frac{-24}{48}
=-1/2
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24}{2*24}=\frac{24}{48}
=1/2
$